os.path.join()函数：连接两个或更多的路径名组件
1.如果各组件名首字母不包含'/'，则函数会自动加上
demo1
| 1 2 3 4 5 6 7 8 | import os
Path1 = 'home'
Path2 = 'develop'
Path3 = 'code'
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)
|
输出：
Path10 = homedevelopcode
Path20 = home\develop\code
2.如果有一个组件是一个绝对路径，则在它之前的所有组件均会被舍弃
demo2
| 1 2 3 4 5 6 7 8 9 10 | import os
Path1 = '/home'
Path2 = 'develop'
Path3 = 'code'
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1, Path2, Path3)
Path30 = os.path.join(Path2, Path1, Path3)
print('Path10 = ',Path10)
print('Path20 = ',Path20)
print('Path30 = ',Path30)
|
输出：
Path10 = /homedevelopcode
Path20 = /home\develop\code
Path30 = /home\code
3.如果最后一个组件为空，则生成的路径以一个'/'分隔符结尾
demo3
| 1 2 3 4 5 6 7 8 9 | import os
Path1 = 'home'
Path2 = 'develop'
Path3 = ''
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1, Path2, Path3)
Path30 = os.path.join(Path2, Path1, Path3)
print('Path10 = ',Path10)
print('Path20 = ',Path20)
|
输出：
Path10 = homedevelop
Path20 = home\develop\
转载自：https://www.jb51.net/article/171478.htm
